A Plant Cell In A Hypotonic Solution Quizlet / Water Balance Plants Html 07 13waterbalancep Jpg / D) the cell will remain the same size because the solution outside the cell is isotonic.
byJoshua Albrecht-0
A Plant Cell In A Hypotonic Solution Quizlet / Water Balance Plants Html 07 13waterbalancep Jpg / D) the cell will remain the same size because the solution outside the cell is isotonic.. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc. D) the cell will remain the same size because the solution outside the cell is isotonic. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution.
B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. D) the cell will remain the same size because the solution outside the cell is isotonic.
D) the cell will remain the same size because the solution outside the cell is isotonic. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc.
C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc.
C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. D) the cell will remain the same size because the solution outside the cell is isotonic. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc.
C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. D) the cell will remain the same size because the solution outside the cell is isotonic. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc.
The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. D) the cell will remain the same size because the solution outside the cell is isotonic. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc.
C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc.
B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc. D) the cell will remain the same size because the solution outside the cell is isotonic. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc.
B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc. D) the cell will remain the same size because the solution outside the cell is isotonic. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution.
C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc. D) the cell will remain the same size because the solution outside the cell is isotonic. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution.
B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc.
D) the cell will remain the same size because the solution outside the cell is isotonic. B) the cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the rbc. The data in the graph are the result of a paramecium being placed in a hypertonic salt solution. C) the cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the rbc.
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